**Problem 6**

Sixth problem from project Euler.

This one was surprisingly easy, I remember having issue with this problem back at uni while learning C#. This time around it seemed quite simple

**Question:**

*The sum of the squares of the first ten natural numbers is,*

*1*

^{2}+ 2^{2}+ ... + 10^{2}= 385*The square of the sum of the first ten natural numbers is,*

*(1 + 2 + ... + 10)*

^{2}= 55^{2}= 3025*Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.*

*Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.*

Answer:

public class problem6 { public static void main(String[] args) { double rootSum = 0; double sum = 0; for(double i = 0; i < 101; i++){ sum += i; double sqr = i * i; rootSum += sqr; } System.out.println((int)((sum * sum)-rootSum)); } }

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